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JCECE Medical JCECE Medical Solved Paper-2014

  • question_answer
    50 mL of 1 M oxalic acid (molar mass =126) is shaken with 0.5 g of wood charcoal. The final concentration of the solution after adsorption is 0.5 M. What is the amount of oxalic acid adsorbed per gram of carbon?

    A)  3.15               

    B) (6) 1.575

    C)  6.30              

    D)  12.60

    Correct Answer: C

    Solution :

     Weight of 50 mL of 1 M oxalic acid \[w=\frac{NEV}{1000}\] (Here,\[N=m\]) \[=\frac{1\times 126\times 50}{1000}\] \[=6.3\,g\] Similarly weight of 50 mL of 0.5 M oxalic acid \[=\frac{0.5\times 126\times 50}{1000}\] \[=3.15\,g\] Adsorbed oxalic acid on 0.5 g charcoal \[=6.3-3.15\] \[=3.15g\] Amount of oxalic acid adsorbed per gram of charcoal \[=\frac{3.15}{0.5}\] \[=6.3\]


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