A) \[~-\text{ }44\text{ kcal}\]
B) \[44\text{ kcal}\]
C) \[~-\text{ }22\text{ kcal}\]
D) \[\text{ }\!\!~\!\!\text{ 22 kcal}\]
Correct Answer: C
Solution :
\[\frac{1}{2}{{H}_{2}}+\frac{1}{2}{{C}_{2}}\xrightarrow{{}}HCl\] \[\Delta \Eta =\sum{B{{E}_{\text{reactants}}}}-\sum{B{{E}_{\text{products}}}}\] \[=\left[ \frac{1}{2}BE({{H}_{2}})+\frac{1}{2}BE(C{{l}_{2}}) \right]-BE(HCl)\] \[=\left[ \left( \frac{1}{2}\times 104 \right)+\left( \frac{1}{2}\times 58 \right) \right]-103\] \[=(52+29)-103\] \[=-22\,kcal\]You need to login to perform this action.
You will be redirected in
3 sec