A) 3.15
B) (6) 1.575
C) 6.30
D) 12.60
Correct Answer: C
Solution :
Weight of 50 mL of 1 M oxalic acid \[w=\frac{NEV}{1000}\] (Here,\[N=m\]) \[=\frac{1\times 126\times 50}{1000}\] \[=6.3\,g\] Similarly weight of 50 mL of 0.5 M oxalic acid \[=\frac{0.5\times 126\times 50}{1000}\] \[=3.15\,g\] Adsorbed oxalic acid on 0.5 g charcoal \[=6.3-3.15\] \[=3.15g\] Amount of oxalic acid adsorbed per gram of charcoal \[=\frac{3.15}{0.5}\] \[=6.3\]You need to login to perform this action.
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