A) 321 Hz
B) 298 Hz
C) 289 Hz
D) 280 Hz
Correct Answer: B
Solution :
The component of velocity of source along line joining \[{{v}_{s}}={{v}_{1}}\cos {{45}^{o}}=36\times \frac{1}{\sqrt{2}}\] \[=5\sqrt{2}\,m/s\] Component of velocity of observer along line joining \[{{v}_{0}}={{v}_{2}}\cos {{45}^{o}}\] \[=72\,\,\times \,\frac{1}{\sqrt{2}}\] \[=10\sqrt{2}\] The frequency of horn \[n=\frac{v+{{v}_{0}}}{v-{{v}_{s}}}\] \[n=\frac{330+10\sqrt{2}}{330-5\sqrt{2}}\times 280\] \[=\frac{344}{323}\times 280=298\,Hz\]You need to login to perform this action.
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