A) 1960J
B) 196J
C) 1.96 J
D) 196kJ
Correct Answer: A
Solution :
\[F=20\text{ }kg-wt=20\times 9.8\text{ }N\] \[\theta ={{60}^{o}}\]and \[s=20\,m\] Work done \[=Fs\cos \theta \] \[=20\times 9.8\times 20\times \cos {{60}^{o}}\] \[=1960\,J\]You need to login to perform this action.
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