A)
B)
C)
D) None of these
Correct Answer: C
Solution :
Number of hybrid orbitals = number of \[bp+\]number of \[lp\] \[=5+1=6\] Thus, hybridisation is \[\text{s}{{\text{p}}^{\text{3}}}{{\text{d}}^{\text{2}}}\]but geometry due to the presence of one lone pair is square pyramidal.You need to login to perform this action.
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