A) 57.0 kJ
B) 11.4 kJ
C) 28.5kJ
D) 34.9kJ
Correct Answer: B
Solution :
0.2 mole of KOH will neutralise 0.2 mole of \[\text{HN}{{\text{O}}_{\text{3}}}\text{.}\] Thus, heat evolved \[=57\times 0.2=11.4\text{ }kJ\]You need to login to perform this action.
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