A) 8.1%
B) 10.1%
C) 11.1%
D) 9.1%
Correct Answer: D
Solution :
Suppose, G is the resistance of galvanometer and \[{{I}_{g}}\]is the current for full scale deflection. If\[\text{I}\]is the maximum current, then \[{{I}_{g}}\times G=(I-{{I}_{g}})S\] Given. \[G=50\,\Omega \]and \[S=5\,\Omega \] \[\therefore \]\[\frac{{{I}_{g}}}{I}=\frac{S}{G+S}=\frac{5}{50+5}=\frac{5}{55}=\frac{1}{11}\] \[\Rightarrow \] \[{{I}_{g}}=\frac{I}{11}\]or \[\frac{{{I}_{g}}}{I}=\frac{1}{11}\] or \[\frac{{{I}_{g}}}{I}%=\frac{1}{11}\times 100%\approx 9.1%\]You need to login to perform this action.
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