Solved papers for JEE Main & Advanced AIEEE Solved Paper-2004

done AIEEE Solved Paper-2004 Total Questions - 3

• question_answer1) What is the equilibrium expression for the reaction \[{{P}_{4}}(s)+5{{O}_{2}}(g){{P}_{4}}{{O}_{10}}(s)?\]
  A)
  \[{{K}_{c}}=\frac{[{{P}_{4}}{{O}_{10}}]}{[{{P}_{4}}]{{[{{O}_{2}}]}^{5}}}\]
  done clear
  B)
         \[{{K}_{c}}=\frac{[{{P}_{4}}{{O}_{10}}]}{5[{{P}_{4}}][{{O}_{2}}]}\]
  done clear
  C)
                         \[{{K}_{c}}={{[{{O}_{2}}]}^{5}}\]               
  done clear
  D)
         \[{{K}_{c}}=\frac{1}{{{[{{O}_{2}}]}^{5}}}\]
  done clear
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• question_answer2) For the reaction, \[CO(g)+C{{l}_{2}}(g)COC{{l}_{2}}(g),\]the\[{{K}_{p}}/{{K}_{c}}\]is equal to
  A)
  \[1/RT\]           
  done clear
  B)
        RT                          
  done clear
  C)
  \[\sqrt{RT}\]             
  done clear
  D)
         1.0
  done clear
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• question_answer3) The equilibrium constant for the reaction \[{{N}_{2}}(g)+{{O}_{2}}(g)2NO(g)\] at temperature T is \[4\times {{10}^{-4}}\]. The value of\[{{K}_{c}}\] for the reaction \[NO(g)\frac{1}{2}{{N}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\]at the same temperature is
  A)
  \[2.5\times {{10}^{2}}\]                
  done clear
  B)
  50                          
  done clear
  C)
         \[4\times {{10}^{-4}}\]         
  done clear
  D)
         0.02
  done clear
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