Solved papers for JEE Main & Advanced JEE Main Solved Paper-2016

done JEE Main Solved Paper-2016 Total Questions - 1

• question_answer1) At 300 K and 1 atm, 15 mL of a gaseous hydrocarbon requires 375 mL air containing 20% \[{{O}_{2}}\] by volume for complete combustion. After combustion the gases occupy 330 mL. Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is :- [JEE Main Solved Paper-2016 ]
  A)
  \[{{C}_{4}}{{H}_{10}}\]                  
  done clear
  B)
  \[{{C}_{3}}{{H}_{6}}\]
  done clear
  C)
  \[{{C}_{3}}{{H}_{8}}\]                    
  done clear
  D)
  \[{{C}_{4}}{{H}_{8}}\]
  done clear
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