Solved papers for JEE Main & Advanced JEE Main Online Paper (Held on 9 April 2013)
done JEE Main Online Paper (Held on 9 April 2013) Total Questions - 1
question_answer1) Let\[f(x)=\frac{{{x}^{2}}-x}{{{x}^{2}}+2x},x\ne 0,-2.\]Then\[\frac{d}{dx}\left[ {{f}^{-1}}(x) \right]\] (wherever it is defined) is equal to :
JEE Main Online Paper (Held On 09 April 2013)