Solved papers for JEE Main & Advanced JEE Main Paper (Held on 7 May 2012)

done JEE Main Paper (Held on 7 May 2012) Total Questions - 2

• question_answer1) The parabola\[{{y}^{2}}=x\] divides the circle \[{{x}^{2}}+{{y}^{2}}=2\]into two parts whose areas are in the ratio   JEE Main Online Paper (Held On 07 May 2012)
  A)
  \[9\pi +2:3\pi -2\]           
  done clear
  B)
                         \[9\pi -2:3\pi +2\]
  done clear
  C)
                         \[7\pi -2:2\pi -3\]            
  done clear
  D)
                         \[7\pi +2:3\pi +2\]
  done clear
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• question_answer2) Statement 1:\[y=mx-\frac{1}{m}\]is always a tangent to the parabola, \[{{y}^{2}}=-4x\]for all non-zero values of w. Statement 2: Every tangent to the parabola, \[{{y}^{2}}=-4x\] will meet its axis at a point whose abscissa is non-negative.   JEE Main Online Paper (Held On 07 May 2012)
  A)
  Statement 1 is true, Statement 2 is true; Statement 2 is a correct explanation of Statement 1.
  done clear
  B)
                         Statement 1 is false, Statement 2 is true.
  done clear
  C)
                         Statement 1 is true. Statement 2 is false.
  done clear
  D)
                         Statement 1 is true. Statement 2 is true, Statement 2 is not a correct explanation of Statement 1.
  done clear
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