Solved papers for JEE Main & Advanced AIEEE Solved Paper-2004

done AIEEE Solved Paper-2004 Total Questions - 1

• question_answer1) An\[\alpha -\]particle of energy\[5\text{ }MeV\]is scattered through\[180{}^\circ \,\]by a fixed uranium nucleus. The distance of the closest approach is of the order of
  A)
  \[1{AA}\]                                          
  done clear
  B)
  \[{{10}^{-10}}cm\]          
  done clear
  C)
  \[{{10}^{-12}}cm\]          
  done clear
  D)
  \[{{10}^{-15}}cm\]
  done clear
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