Solved papers for JEE Main & Advanced JEE Main Paper (Held On 9 April 2014)

done JEE Main Paper (Held On 9 April 2014) Total Questions - 1

• question_answer1) A transverse wave is represented by\[y=\frac{10}{\pi }\sin \left( \frac{2\pi }{T}t-\frac{2\pi }{\lambda }x \right)\] For what value of the wavelength the wave velocity is twice the maximum particle velocity?   [JEE Main Online Paper ( Held On 09 Apirl  2014  )
  A)
  40 cm                   
  done clear
  B)
  20 cm
  done clear
  C)
  10 cm                   
  done clear
  D)
  60 cm
  done clear
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