A) \[\frac{1}{3}\]
B) \[\frac{4}{\sqrt{3}}\]
C) \[\frac{1}{\sqrt{3}}\]
D) \[\frac{2}{\sqrt{3}}\]
Correct Answer: D
Solution :
Given \[{{x}^{2}}+{{y}^{2}}=4\] equation of tangent \[\Rightarrow \]\[\sqrt{3}x+y=4\] ...(1) Equation of normal \[x-\sqrt{3}y=0\] ...(2) Coordinate of \[T\left( \frac{4}{\sqrt{3}},0 \right)\] \[\therefore \]Area of triangle \[=\frac{2}{\sqrt{3}}\]You need to login to perform this action.
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