A) \[2\sqrt{3}\]
B) \[\sqrt{3}\]
C) \[\sqrt{6}\]
D) \[\frac{2}{3}\sqrt{3}\]
Correct Answer: A
Solution :
\[h=2r\sin \theta \] \[a=2r\cos \theta \] \[\text{v}=\pi {{(r\cos \theta )}^{2}}(2rsin\theta )\] \[\text{v}=2{{\pi }^{2}}{{\cos }^{2}}\theta \sin \theta \] \[\frac{\text{dv}}{d\theta }=\pi {{r}^{3}}(-2\cos \theta {{\sin }^{2}}\theta +{{\cos }^{3}}\theta )=0\] or\[\tan \theta =\frac{1}{\sqrt{2}}\] \[\because \]\[h=2\times 3\times \frac{1}{\sqrt{3}}\] \[=2\sqrt{3}\]You need to login to perform this action.
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