A) 40 m
B) 51 m
C) 32 m
D) 20 m
Correct Answer: C
Solution :
Range\[=\sqrt{2R{{h}_{T}}}+\sqrt{2R{{h}_{R}}}\] \[50\times {{10}^{3}}=\sqrt{2\times 6400\times {{10}^{3}}\times {{h}_{T}}}\] +\[\sqrt{2\times 6400\times {{10}^{3}}\times 70}\] by solving \[{{h}_{T}}=32m\]You need to login to perform this action.
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