A) \[\sqrt{2}\left( \frac{{{\mu }_{0}}}{4\pi } \right)\frac{M}{{{(d/2)}^{3}}}\times q\text{v}\]
B) \[\left( \frac{{{\mu }_{0}}}{4\pi } \right)\frac{2M}{{{(d/2)}^{3}}}\times q\text{v}\]
C) \[\left( \frac{{{\mu }_{0}}}{4\pi } \right)\frac{M}{{{(d/2)}^{3}}}\times q\text{v}\]
D) 0
Correct Answer: D
Solution :
\[{{B}_{1}}=2\left( \frac{{{\mu }_{0}}}{4\pi } \right)\frac{M}{{{(d/2)}^{3}}};\,\,\,\,\,\,\,{{B}_{2}}=\left( \frac{{{\mu }_{0}}}{4\pi } \right)\frac{2M}{{{(d/2)}^{3}}}\] \[{{B}_{1}}={{B}_{2}}\] \[\Rightarrow \]\[{{B}_{net}}\] is at \[{{45}^{o}}(\theta ={{45}^{o}})\] velocity of charge and \[{{B}_{net}}\]are parallel so by \[\vec{F}=q\left( \text{\vec{v}}\times \text{\vec{B}} \right)\]force on charge particle is zero.You need to login to perform this action.
You will be redirected in
3 sec