A) \[x+3y+z=4\]
B) \[xyz=0\]
C) \[x3y2z=2\]
D) \[2xz=2\]
Correct Answer: B
Solution :
The required plane is \[\left( 2xy4 \right)+\lambda \left( y+2z4 \right)=0\] it passes through (1, 1, 0) \[\Rightarrow \]\[\left( 214 \right)+\lambda \left( 14 \right)=0\] \[\Rightarrow \] \[33\lambda =0\Rightarrow \lambda =1\] \[\Rightarrow \] \[xyz=0\]You need to login to perform this action.
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