A) \[10\,\,kHz\]
B) \[7.5\,\,kHz\]
C) \[5\,\,kHz\]
D) \[2.5\,\,kHz\]
Correct Answer: C
Solution :
\[\ell =60\,\,cm\] \[\rho =2.7\times {{10}^{3}}kg/{{m}^{3}}\] \[y=9.27\times {{10}^{10}}Pa\] For fundamental frequency\[\frac{\lambda }{2}=\ell \Rightarrow \lambda =2\ell \] \[f=\frac{v}{\lambda }\Rightarrow f=\frac{1}{2\ell }\sqrt{\frac{Y}{\rho }}\] \[f=\frac{1}{2\times 06}\sqrt{\frac{9.27\times {{10}^{10}}}{2.7\times {{10}^{3}}}}\] \[f\approx 5kHz\]You need to login to perform this action.
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