A) 85
B) 95
C) 195
D) 185
Correct Answer: B
Solution :
\[{{x}^{2}}=y-6\] tangent at\[\text{P(1, 7)}\] \[\text{x}\text{.1=}\left( \frac{y+7}{2} \right)-6\] \[\Rightarrow \text{2x -- y + 5 = 0 (eq}\text{. of tangent)}\]) \[r=\sqrt{64+36-c}\] \[r=\sqrt{100-c}\] Condition of tangency\[\Rightarrow p=r\] \[\Rightarrow \left| \frac{2(-8)-(-6)+5}{\sqrt{{{2}^{2}}+{{1}^{2}}}} \right|=\sqrt{100-c}\] \[\Rightarrow \sqrt{5}=\sqrt{100-c}\] \[\Rightarrow c=95\]You need to login to perform this action.
You will be redirected in
3 sec