A) \[2.2\,\,N/m\]
B) \[5.5\,\,N/m\]
C) \[6.4\,\,N/m\]
D) \[7.1\,\,N/m\]
Correct Answer: D
Solution :
\[kx=m{{\omega }^{2}}X\] \[\Rightarrow k=m{{\omega }^{2}}\] \[=\frac{108}{6.02\times {{10}^{23}}}\times {{(2\pi \times {{10}^{12}})}^{2}}\times {{10}^{-3}}\] \[k\approx 7.1N/m\]You need to login to perform this action.
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