JEE Main & Advanced JEE Main Online Paper (Held On 08 April 2018)

  • question_answer
    If \[\alpha ,\,\,\beta \,\,\in \,\,C\] are the distinct roots, of the equation \[{{x}^{2}}-x+1=0,\] then \[{{\alpha }^{101}}+{{\beta }^{107}}\] is equal to: [JEE Main Online 08-04-2018]

    A)  1                                

    B)  2

    C)  -1                               

    D)  0

    Correct Answer: A

    Solution :

     1 Roots of \[{{x}^{2}}-x+1=0\]are \[(-\omega ,-{{\omega }^{2}})\] \[\Rightarrow \alpha =-\omega ,\beta =-{{\omega }^{2}}\] \[\Rightarrow {{\alpha }^{101}}+{{\beta }^{107}}\] \[\Rightarrow {{(-\omega )}^{101}}+{{(-{{\omega }^{2}})}^{107}}\] \[\Rightarrow -{{\omega }^{2}}-\omega =1\]


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