A) \[\frac{1}{3}\]
B) \[\sqrt{\frac{2}{3}}\]
C) \[\frac{2}{\sqrt{3}}\]
D) \[\frac{2}{3}\]
Correct Answer: C
Solution :
Foot of perpendicular of point A on plane \[\frac{x-4}{1}=\frac{y-(-1)}{1}=\frac{z-3}{1}=-\frac{(-1)}{3}\] \[A(13/3,-2/3,10/3)\] Similarly, \[B(14/3,-4/3,11/3)\] \[AB=\sqrt{{{(14/3-13/3)}^{2}}+{{(-4/3+2/3)}^{2}}+{{(11/3-10/3)}^{2}}}\] \[=\sqrt{\frac{2}{3}}\]You need to login to perform this action.
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