A) contains exactly two elements.
B) contains exactly four elements.
C) is an empty set.
D) contains exactly one element.
Correct Answer: A
Solution :
\[2\left| \sqrt{x}-3 \right|+{{\left( \sqrt{x} \right)}^{2}}-6\sqrt{x}+6=0\] \[2\left| \sqrt{x}-3 \right|+{{\left( \sqrt{x}-3 \right)}^{2}}-3=0\] \[Let\left| \sqrt{x}-3 \right|=t\] \[\therefore {{t}^{2}}+2t-3=0\] \[t=1\] or \[-3\](Not possible) \[\therefore \sqrt{x}=2,4\] \[\therefore x=4or16\]
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