A) \[\text{+3, 0, and +6}\]
B) \[\text{+3, 0, and +4}\]
C) \[\text{+3, +4 and +6}\]
D) \[\text{+3, +2 and +4}\]
Correct Answer: A
Solution :
\[\Rightarrow [Cr{{({{H}_{2}}O)}_{6}}]C{{l}_{3}}\to \] be oxidation state of chromium \[\text{x+6(0)=+3}\] \[\text{x = +3}\] \[\Rightarrow \]\[[Cr{{({{C}_{6}}{{H}_{6}})}_{2}}]\] \[x+2(0)=0\] \[x=0\] \[\Rightarrow {{\text{k}}_{\text{2}}}\text{ }\!\![\!\!\text{ Cr(CN}{{\text{)}}_{\text{2}}}{{\text{(O)}}_{\text{2}}}\text{(}{{\text{O}}_{\text{2}}}\text{)(N}{{\text{H}}_{\text{3}}}\text{) }\!\!]\!\!\text{ }\] \[x-2+2(-2)+1(-2)+0=-2\] \[x-2-4-2=-2\] \[x-6=0\] \[x=+6\]You need to login to perform this action.
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