A)
B)
C)
D)
Correct Answer: D
Solution :
Diazonium, nitro and ring containing nitrogen do not show Kjeldahl method because it is not interconvert into ammonium ion so the answer will be (3) \[\text{Ph-N}{{\text{H}}_{\text{2}}}\xrightarrow{{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}}{{\text{(N}{{\text{H}}_{\text{4}}}\text{)}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\xrightarrow{{}}\text{Kjeldahl method}\]
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