A) \[\text{P}{{\text{H}}_{\text{3 }}}\text{and SiC}{{\text{l}}_{\text{4}}}\]
B) \[\text{BC}{{\text{l}}_{3}}\] and \[\text{AlC}{{\text{l}}_{\text{3}}}\]
C) \[\text{P}{{\text{H}}_{3}}\] and \[\text{BC}{{\text{l}}_{\text{3}}}\]
D) \[\text{AlC}{{\text{l}}_{3}}\] and \[\text{SiC}{{\text{l}}_{\text{4}}}\]
Correct Answer: B , D
Solution :
(b) and (d) \[\text{BC}{{\text{l}}_{\text{3}}}\] and \[\text{AlC}{{\text{l}}_{\text{3}}}\] both are hypovalent compounds due to incomplete octet on central atom. Thus both can act as Lewis acid. \[\text{SiC}{{\text{l}}_{\text{4}}}\] can also act as Lewis acid due to presence of vacant 3d-orbitals on silicon atom in its vacant d-orbital. Option (a) and (c) both are correct.Solution :
(b) and (d) \[\text{BC}{{\text{l}}_{\text{3}}}\] and \[\text{AlC}{{\text{l}}_{\text{3}}}\] both are hypovalent compounds due to incomplete octet on central atom. Thus both can act as Lewis acid. \[\text{SiC}{{\text{l}}_{\text{4}}}\] can also act as Lewis acid due to presence of vacant 3d-orbitals on silicon atom in its vacant d-orbital. Option (a) and (c) both are correct.
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