A)
B)
C)
D)
Correct Answer: B
Solution :
\[{{\phi }_{outer}}=({{\mu }_{0}}nKt{{e}^{-\alpha t}})4\pi {{R}^{2}}\] \[\varepsilon =\frac{-d\phi }{dt}=-C{{e}^{-\alpha t}}[1-\alpha t]\] \[{{i}_{induced}}=\frac{-C{{e}^{-\alpha t}}[1-at]}{(Resistance)}\] At\[t=0\,\,{{i}_{induced}}=-\text{v}e.\]You need to login to perform this action.
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