A) \[5.65\text{ }\times \text{ }{{10}^{2}}J\]
B) \[2.26\text{ }\times {{10}^{3}}J\]
C) \[5.17\text{ }\times \text{ }{{10}^{2}}\,J~\]
D) \[3.39\text{ }\times \text{ }{{10}^{3}}\,J\]
Correct Answer: C
Solution :
\[{{X}_{L}}=100\pi \,\,\times \,\,20\times {{10}^{-}}^{3}\] \[{{X}_{L}}=2\,\pi \,\,=\,\,6.28\,\Omega \] \[{{X}_{C}}=\frac{1}{100\pi \,\times \,120\,\times \,{{10}^{-6}}}\,\,=\,\,\frac{250}{3\,\pi }\] \[{{X}_{C}}=\frac{{{10}^{6}}}{12000\,\pi }\,\,=\,\,\frac{{{10}^{3}}}{12\,\pi }\] \[\left| {{X}_{L}}-{{X}_{C}} \right|=20.25\] \[Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}\] Energy \[=\,\,\,{{I}^{2}}_{rms}R\,\,\times \,\,t\] \[=\text{ }5.17\times {{10}^{2}}\,J\]You need to login to perform this action.
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