A) \[\frac{1}{N}\]
B) N
C) \[{{N}^{2}}\]
D) \[\frac{1}{{{N}^{2}}}\]
Correct Answer: D
Solution :
\[2\pi \,R=L\] \[N2\pi \,r=L\] \[R=\frac{L}{2\,\pi }\] \[r=\frac{L}{N.2\,\pi }\] \[{{B}_{L}}\,\,=\,\,\frac{{{\mu }_{0}}I\,.\,2\pi }{2.\,L}\] \[{{B}_{c}}\,\,=\,\,\frac{{{\mu }_{0}}.NIN\,.\,2\pi }{2.\,L}\] \[\frac{{{B}_{L}}}{{{B}_{C}}}\,\,=\,\,\frac{\frac{{{\mu }_{0}}I2\,\pi }{2\,L}}{\frac{{{\mu }_{0}}.{{N}^{2}}I\,.\,2\pi }{2.\,L}}=\frac{1}{{{N}^{2}}}\] Option is correct.You need to login to perform this action.
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