A) 6.0 m
B) 9.6 m
C) 2.9 m
D) 4.8 m
Correct Answer: D
Solution :
\[r\,\,=\,\,2\,cm\] \[a=\pi {{\left( 2\times {{10}^{-2}} \right)}^{2}}=\pi \,\,\times 4\times {{10}^{-}}^{4}{{m}^{2}}\] \[\because \,\,A>>a\] \[\Rightarrow \,\,\,V\,\,=\,\,\sqrt{2gh}\] Volume flow rate = \[Av=0.74{{m}^{3}}/min\] \[=\,\,\frac{0.74}{60}\,{{m}^{3}}/\sec \] \[4\pi \,\,\times \,\,{{10}^{-4}}\,v=\,\,\frac{0.74}{60}\,\] \[v\,\,=\,\,\frac{0.74}{4\pi \,\times \,{{10}^{-4}}\,\times \,\,60}\,\,=\,\frac{0.74\,\times {{10}^{4}}}{4\times 3.14\,\times 60}\] \[v\,\,=\,\,\frac{7400}{12.56\,\times \,60}\,\,=\,\,\sqrt{2gh}\] \[\,\,\frac{740}{75.36}\,\,=\,\,\sqrt{2gh}\] \[h\,\,\approx \,\,4.8\,m\]You need to login to perform this action.
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