A) \[\frac{K{{\in }_{0}}{{a}^{2}}}{2d\,(K+1)}\]
B) \[\frac{K{{\in }_{0}}{{a}^{2}}}{d\,(K-1)}\,\,In\,\,K\]
C) \[\frac{K{{\in }_{0}}{{a}^{2}}}{d}\,\,In\,\,K\]
D) \[\frac{1}{2}\,\,\,\frac{K{{\in }_{0}}{{a}^{2}}}{d}\]
Correct Answer: B
Solution :
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