A) 6 mC
B) 14 mC
C) 7 mC
D) 21 mC
E) None of These
Correct Answer: E
Solution :
[Bonus] \[\Delta \,q\,\,=\,\,\frac{\Delta \,\phi }{R}\] \[B\text{ }=\text{ }0.4\text{ }sin\text{ }50\text{ }\pi t\] \[\phi \text{ }=\text{ }B.\,A\text{ }=\text{ }\left( 0.4\text{ }sin\text{ }50\text{ }\pi t \right)\text{ }3.5\text{ }\times \text{ }{{10}^{-3}}\] \[=\,\,\,1.4\text{ }\times \text{ }{{10}^{-3}}\,sin\text{ }50\pi t\] At \[t=\text{ }0\text{ };\text{ }\phi \text{ }=\text{ }0\] \[At\text{ }t=\text{ }10\,\,\times \,\,{{10}^{-3}}\,s\] \[\phi \text{ }=\text{ }1.4\,\,\times \,\,{{10}^{-3}}\,\,sin\,(50\pi \,\,.\,{{10}^{-2}})\] \[=\text{ }1.4\,\,\times \,{{10}^{-3}}\] \[\Rightarrow \,\,\,\,\Delta \,q\,\,=\,\,\frac{1.4\,\,\times \,\,{{10}^{-3}}}{10}\,\,=\,\,0.14\,\,\times \,\,{{10}^{-3}}\] = 0.14 mC.You need to login to perform this action.
You will be redirected in
3 sec