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JEE Main & Advanced JEE Main Paper (Held on 10-4-2019 Afternoon)

  • question_answer
    The figure represents a voltage regulator circuit using a Zener diode. The breakdown voltage of the Zener diode is 6V and the load resistance is \[{{R}_{L}}=4k\Omega .\]The series resistance of the circuit is \[{{R}_{i}}=1\,k\Omega .\]If the battery voltage \[{{V}_{B}}\]varies from 8V to 16V, what are the minimum and maximum values of the current through Zener diode? [JEE Main 10-4-2019 Afternoon]

    A) 0.5 mA ; 6 mA            

    B) 0.5 mA ; 8.5 Ma

    C) 1.5 mA ; 8.5 mA

    D)   1 mA ; 8.5 mA

    Correct Answer: B

    Solution :

    \[At\,{{V}_{B}}=8V\]           \[{{i}_{L}}=\frac{6\times {{10}^{-3}}}{4}=1.5\times {{10}^{-3}}A\]           \[{{i}_{R}}=\frac{8-6\times {{10}^{-3}}}{1}=2\times {{10}^{-3}}A\]           \[\therefore \]\[{{i}_{zener\,diode}}={{i}_{R}}-{{i}_{load}}\]           \[=0.5\times {{10}^{-3}}A\]           \[At\,{{V}_{B}}=16V\]           \[{{i}_{L}}=1.5\times {{10}^{-3}}A\]           \[{{i}_{R}}=\frac{(16-6)\times {{10}^{-3}}}{1}=10\times {{10}^{-3}}A\]           \[\therefore \]\[{{i}_{zener}}diode={{i}_{R}}-{{i}_{L}}\] \[=8.5\times {{10}^{-3}}A\]


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