A) \[a{{\alpha }^{2}}-b\alpha -a=0\]
B) \[a{{\alpha }^{2}}+b\alpha -a=-2{{\alpha }^{2}}\]
C) \[a{{\alpha }^{2}}+b\alpha +a=0\]
D) \[a{{\alpha }^{2}}-b\alpha -a=1\]
Correct Answer: D
Solution :
\[fog(x)=(-x)\Rightarrow (fg(\alpha ))=-\alpha =b\] \[(fg(x))'=-1\Rightarrow (fg(\alpha ))'=-1=a\]You need to login to perform this action.
You will be redirected in
3 sec