A) \[\frac{6}{5}\]
B) \[\frac{8}{5}\]
C) \[\frac{2}{3}\]
D) \[\frac{3}{2}\]
Correct Answer: B
Solution :
Let a is first term and d is common difference then, \[a+5d=2\] (given) ...(1) \[f(d)=(2-5d)(2-2d)(2-d)\] \[f'(d)=0\Rightarrow d=\frac{2}{3},\frac{8}{5}\] \[f''(d)<0\,\text{at}\,\,d=8/5\]\[\Rightarrow d=\frac{8}{5}\]You need to login to perform this action.
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