A) \[18\mu T\]
B) \[3\mu T\]
C) \[1\mu T\]
D) \[9\mu T\]
Correct Answer: A
Solution :
\[B=3\left[ \frac{{{\mu }_{0}}i}{4\pi r}(sin{{60}^{o}}+sin{{60}^{o}}) \right]\] Here, \[r=\frac{a}{2\sqrt{3}}=\frac{1}{2\sqrt{3}}\] \[B=3\left[ \frac{4\pi \times {{10}^{-7}}\times 10\times 2\sqrt{3}}{4\pi \times 1}\left[ \frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2} \right] \right]\] \[B=18\times {{10}^{-6}}=18\mu T\]You need to login to perform this action.
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