A) \[\frac{3m}{\pi }\]
B) \[\frac{4m}{\pi }\]
C) \[\frac{2m}{\pi }\]
D) \[\frac{m}{\pi }\]
Correct Answer: B
Solution :
\[m=NIA=1\times I\times {{a}^{2}}\]here a = side of square Now, \[4a=2\pi r\] \[r=\frac{2a}{\pi }\] For circular loop \[m'=1\times I\times \pi {{r}^{2}}\] \[=1\times I\times \pi \times {{\left( \frac{2a}{\pi } \right)}^{2}}\] \[m'=\frac{4m}{\pi }\]You need to login to perform this action.
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