A) \[2.0\times {{10}^{3}}m/s\]
B) \[3.0\times {{10}^{4}}m/s\]
C) \[1.5\times {{10}^{2}}m/s\]
D) \[1.0\,m/s\]
Correct Answer: A
Solution :
\[{{W}_{E}}=-[\Delta U]={{U}_{i}}-{{U}_{F}}=\frac{1}{2}m{{\text{v}}^{2}}\] \[U=\frac{k{{q}_{1}}{{q}_{2}}}{r}\] \[\frac{(9\times {{10}^{9}})\times {{10}^{-12}}}{{{10}^{-3}}}-\frac{(9\times {{10}^{9}})\times {{10}^{-12}}}{9\times {{10}^{-3}}}=\frac{1}{2}\times (4\times {{10}^{-6}}){{v}^{2}}\] \[{{v}^{2}}=4\times {{10}^{6}}\] \[v=2\times {{10}^{3}}m/s\]You need to login to perform this action.
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