A) \[1\times {{10}^{5}}{{m}^{2}}\]
B) \[5\times {{10}^{5}}{{m}^{2}}\]
C) \[2\times {{10}^{5}}{{m}^{2}}\]
D) \[5\times {{10}^{4}}{{m}^{2}}\]
Correct Answer: B
Solution :
\[{{A}_{1}}{{\text{v}}_{1}}={{A}_{2}}{{\text{v}}_{2}}\] \[{{10}^{-4}}\times 1={{A}_{2}}{{\text{v}}_{2}}\] \[{{A}_{2}}{{\text{v}}_{2}}={{10}^{-4}}\] ?.(1) \[P+\frac{1}{2}\rho (v_{1}^{2}-v_{2}^{2})+\rho gh=P\] \[v_{2}^{2}=v_{1}^{2}+2gh\] \[v_{2}^{{}}=\sqrt{\text{v}_{1}^{2}+2gh}\] \[=\sqrt{1+2\times 10\times 0.15}\] \[\frac{{{10}^{-4}}}{{{A}_{2}}}=2\] \[{{A}_{2}}=5\times {{10}^{-5}}{{m}^{2}}\]You need to login to perform this action.
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