A) 14 cm
B) 20 cm
C) 18 cm
D) 26 cm
Correct Answer: B
Solution :
\[t=\frac{2\times 2\times \sin {{15}^{o}}}{g\,\cos {{30}^{o}}}\] \[S=2\cos {{15}^{o}}\times t-\frac{1}{2}g\sin {{30}^{o}}{{t}^{2}}\] Put values and solve \[S\simeq 20cm\]You need to login to perform this action.
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