A) \[1/4\lambda \]
B) \[1/\lambda \]
C) \[1/2\lambda \]
D) \[2/\lambda \]
Correct Answer: C
Solution :
\[{{N}_{A}}={{N}_{0}}{{e}^{-5\lambda t}}\] \[{{N}_{B}}={{N}_{0}}{{e}^{-\lambda t}}\] \[\frac{{{N}_{A}}}{{{N}_{B}}}=\frac{{{e}^{-5\lambda t}}}{{{e}^{-\lambda t}}}=\frac{1}{{{e}^{2}}}\] \[\Rightarrow {{e}^{-4\lambda t}}={{e}^{-2}}\] \[\Rightarrow 4\lambda t=2\] \[\Rightarrow t=\frac{1}{2\lambda }\]You need to login to perform this action.
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