A) \[2a+2b\]
B) \[2a+\frac{2b}{3}\]
C) \[\frac{2\sqrt{3}}{a}+2b\]
D) \[2a+\frac{2b}{\sqrt{3}}\]
Correct Answer: A
Solution :
From Snell's law \[1.sin60{}^\circ =\mu sin30{}^\circ \] \[\Rightarrow \mu =\sqrt{3}\] Optical path\[=AO+\mu (OB)\] \[=\frac{a}{\cos {{60}^{o}}}+\sqrt{3}\frac{b}{\cos {{30}^{o}}}\]\[=2a+2b\]You need to login to perform this action.
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