A) \[9\]
B) \[8\sqrt{3}\]
C) \[12\sqrt{2}\]
D) \[5\]
Correct Answer: A
Solution :
Tangent at\[\left( 3,-\frac{9}{2} \right)\] \[\frac{3x}{{{a}^{2}}}-\frac{9y}{2{{b}^{2}}}=1\] Comparing this with \[x2y=12\] \[\frac{3}{{{a}^{2}}}=\frac{9}{4{{b}^{2}}}=\frac{1}{12}\] we get a = 6 and \[b=3\sqrt{3}\] \[L(LR)=\frac{2{{b}^{2}}}{a}=9\]You need to login to perform this action.
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