A) \[\frac{1}{\sqrt{30}}\]
B) \[\frac{1}{6\sqrt{10}}\]
C) \[\frac{1}{\sqrt{15}}\]
D) \[\frac{1}{2\sqrt{15}}\]
Correct Answer: C
Solution :
G is the centroid of \[\Delta ABC\] \[G\equiv (2,4,2)\] \[\overrightarrow{OG}=2\hat{i}+4\hat{j}+2\hat{k}\] \[\overrightarrow{OA}=3\hat{i}-\hat{k}\] \[\cos (\angle GOA)=\frac{\overrightarrow{OG}.\overrightarrow{OA}}{|\overrightarrow{OG}|\,\,|\overrightarrow{OA}|}=\frac{1}{\sqrt{15}}\]You need to login to perform this action.
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