JEE Main & Advanced
JEE Main Paper (Held On 10-Jan-2019 Morning)
question_answer
A homogeneous solid cylindrical roller of radius R and mass M is pulled on a cricket pitch by a horizontal force. Assuming rolling without slipping, angular acceleration of the cylinder is-
[JEE Main Online Paper (Held On 10-Jan-2019 Morning]
A)\[\frac{F}{2mR}\]
B)\[\frac{2\,F}{3mR}\]
C)\[\frac{3\,F}{2mR}\]
D) \[\frac{F}{3mR}\]
Correct Answer:
B
Solution :
\[{{_{\tau abt}}_{A\,}}\,=\,\,{{I}_{A\alpha }}\] \[F\times R=\left( \frac{1}{2}M{{R}^{2}}+M{{R}^{2}} \right)\alpha \] \[\alpha \,\,=\,\,\frac{2F}{3mR}\] Note: In this question value of force and its point of application is not given so its answer cannot be given. We are giving its answer by assuming that F is applied at centre of cylinder.