A) \[\frac{1}{8}\]
B) \[\frac{1}{2}\]
C) \[\frac{1}{4}\]
D) \[-\frac{1}{4}\]
Correct Answer: C
Solution :
\[\overrightarrow{AB}=(3-1+3\mu )\widehat{i}\,\,+(2-\mu +1)\widehat{j}+(6-2-5\mu )\widehat{k}\]\[=\,\,(2+3\mu )\widehat{i}+(3-\mu )\widehat{j}+(4-5\mu )\widehat{k}\] \[\overrightarrow{AB}\text{ }\bot \] normal of plane \[(2+3\mu )\left( 1 \right)+(3-u)\left( -4 \right)+(4-5\mu )\left( 3 \right)=0\] \[2-8\mu =0\,\,\Rightarrow \,\,\mu =\frac{1}{4}\]You need to login to perform this action.
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