A) 12
B) 36
C) 14
D) 4
Correct Answer: A
Solution :
\[{{C}_{eq}}\,=\,\frac{{{\varepsilon }_{0}}}{d}\left( \frac{A}{3}\times 10+\frac{A}{3}\times 12+\frac{A}{3}\times 14 \right)\] If whole slab is replaced by single dielectric K then \[C\,\,=\,\,\frac{K\,{{\in }_{0}}\,A}{d}\] Now \[\frac{K\,{{\in }_{0}}\,A}{d}=\,\frac{{{\in }_{0}}A}{d}\left[ \frac{10}{3}+\frac{12}{3}+\frac{14}{3} \right]\] \[K=12\]You need to login to perform this action.
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