A) 25 ke V
B) 500 ke V
C) 100 ke V
D) 1 ke V
Correct Answer: A
Solution :
\[\frac{d}{f}\,=\,\frac{1.22}{v}\,\,\frac{\lambda v}{a}\] \[d\,\,=\,\,1.22\,\,\frac{\lambda }{a}\] \[{{d}_{min}}\] is of order of wavelength of light \[=7.5\times {{10}^{-12}}=0.075\overset{{}^\circ }{\mathop{A}}\,\] \[=7.5\times {{10}^{-12}}=\frac{h}{\sqrt{2mKE}}\] \[0.075\,=\,\frac{12.26}{\sqrt{KE}}\] \[KE\,=\,{{\left( \frac{12.26}{0.075} \right)}^{2}}\,=\,\,25\,ke\,V\]You need to login to perform this action.
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